bytes.Count() function is used to count the number of non-overlapping instances in two byte slices in go.
In function bytes.Count(s, sep []byte), If sep is an empty slice, Count function will returns “1 + the number of UTF-8-encoded code points in s”.
bytes.Count() function prototype:
func Count(s, sep []byte) int or func Count(s []byte, sep []byte) int Input parameters: s: byte slice sep: byte slice
bytes.Count() function return value:
bytes.Count() function returns counts the number of non-overlapping instances of sep in s.
Explanation:
1)
s := []byte("techieindoor")
sep := []byte("e")
Output: 2 i.e total 2 "e" characters / bytes in "techieindoor"
2)
s := []byte("techieindoor")
sep := []byte("")
Output: 13 , If sep is an empty slice, Count returns "1 + the number of UTF-8-encoded code points in s".
3)
s := []byte("jubsslsyesr")
sep := []byte("s")
Output: 4 i.e total 4 "s" characters / bytes in "jubsslsyesr"
4)
b := []byte("jubssrlsyesr")
sep := []byte("sr")
Output: 2 i.e total 2 "sr" in "jubssrlsyesr"
5)
b = []byte{10, 20, 30, 40}
sep = []byte{20, 30}
Output: 1 i.e {20, 30} present only once in {10, 20, 30, 40}
6)
b = []byte{10, 20, 30, 40, 20, 20}
sep = []byte{20}
Output: 3 i.e {20} present 3 times in {10, 20, 30, 40, 20, 20}
Example:
package main
import (
"bytes"
"fmt"
)
func main() {
b := []byte("techieindoor")
sep := []byte("e")
fmt.Println(bytes.Count(b, sep))
b = []byte("techieindoor")
sep = []byte("")
fmt.Println(bytes.Count(b, sep))
b = []byte("jubsslsyesr")
sep = []byte("s")
fmt.Println(bytes.Count(b, sep))
b = []byte("jubssrlsyesr")
sep = []byte("sr")
fmt.Println(bytes.Count(b, sep))
b = []byte{10, 20, 30, 40}
sep = []byte{20, 30}
fmt.Println(bytes.Count(b, sep))
b = []byte{10, 20, 30, 40, 20, 20}
sep = []byte{20}
fmt.Println(bytes.Count(b, sep))
}
Output:
2 13 4 2 1 3
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