Here, We will learn how to get the the natural logarithm of 1 plus its argument x in go. We can get it by using Log1p() function in math package in go golang.
Function prototype:
func Log1p(x float64) float64
Return value:
Log1p() function in math package returns
the natural logarithm of 1 plus its
argument x. It is more accurate than
Log(1 + x) when x is near zero.
Example with code:
package main
import (
"fmt"
"math"
)
func main() {
no := math.Log1p(1.2)
fmt.Println(no)
no = math.Log1p(2.3)
fmt.Println(no)
no = math.Log1p(0.0)
fmt.Println(no)
no = math.Log1p(-2.9)
fmt.Println(no)
}
Output:
0.7884573603642702
1.1939224684724346
0
NaN
To learn more about golang, Please refer given below link:
https://techieindoor.com/go-lang-tutorial/
References:
https://golang.org/doc/
https://golang.org/pkg/