Here, we will help to understand about how to solve Smallest Even Multiple Solution of leetcode 2413 problem with code and algorithm.
You are given a positive integer n. You have to return the smallest positive integer that is a multiple of both 2 and n.
Example:
1) n = 5 Output: 10 Explanation: 10 is a multiple of both 2 and 5 which means 10 can be divided by 2 and 5. 2) n = 10 Output: 10 Explanation: 10 is a multiple of both 2 and 10 which means 10 can be divided by 2 and 10. 3) n = 11 Output: 22 Explanation: 22 is a multiple of both 2 and 11 which means 22 can be divided by 2 and 11.
Smallest Even Multiple solution code in C++
Code 1:
#include <iostream>
using namespace std;
int smallestEvenMultiple(int n) {
return (n & 1 == 1) ? 2 *n : n;
}
int main()
{
cout<<smallestEvenMultiple(10);
return 0;
}
Output:
10
Code 2:
#include <iostream>
using namespace std;
int smallestEvenMultiple(int n) {
if((n & 1) == 0) {
return n;
} else {
return n * 2;
}
}
int main()
{
cout<<smallestEvenMultiple(11);
return 0;
}
Output:
22
Smallest Even Multiple solution code in Go
package main
import "fmt"
func smallestEvenMultiple(n int) int {
if n % 2 == 0 {
return n
}
return n * 2
}
func main() {
fmt.Println(smallestEvenMultiple(13))
}
Output:
26
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